3(4k-7)=2(3k+11)+5

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Solution for 3(4k-7)=2(3k+11)+5 equation: 



3(4k-7)=2(3k+11)+5

We move all terms to the left:

3(4k-7)-(2(3k+11)+5)=0

We multiply parentheses

12k-(2(3k+11)+5)-21=0



We calculate terms in parentheses: -(2(3k+11)+5), so:

2(3k+11)+5

We multiply parentheses

6k+22+5

We add all the numbers together, and all the variables

6k+27

Back to the equation:

-(6k+27)



We get rid of parentheses

12k-6k-27-21=0

We add all the numbers together, and all the variables

6k-48=0

We move all terms containing k to the left, all other terms to the right

6k=48

k=48/6

k=8

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