3(4m+2)+5(2m-6)=64

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Solution for 3(4m+2)+5(2m-6)=64 equation: 



3(4m+2)+5(2m-6)=64

We move all terms to the left:

3(4m+2)+5(2m-6)-(64)=0

We multiply parentheses

12m+10m+6-30-64=0

We add all the numbers together, and all the variables

22m-88=0

We move all terms containing m to the left, all other terms to the right

22m=88

m=88/22

m=4

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