3(4n-5)+7n-11=n

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Solution for 3(4n-5)+7n-11=n equation: 



3(4n-5)+7n-11=n

We move all terms to the left:

3(4n-5)+7n-11-(n)=0

We add all the numbers together, and all the variables

6n+3(4n-5)-11=0

We multiply parentheses

6n+12n-15-11=0

We add all the numbers together, and all the variables

18n-26=0

We move all terms containing n to the left, all other terms to the right

18n=26

n=26/18

n=1+4/9

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