3(4r+5)=5(2r+4)

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Solution for 3(4r+5)=5(2r+4) equation: 



3(4r+5)=5(2r+4)

We move all terms to the left:

3(4r+5)-(5(2r+4))=0

We multiply parentheses

12r-(5(2r+4))+15=0



We calculate terms in parentheses: -(5(2r+4)), so:

5(2r+4)

We multiply parentheses

10r+20

Back to the equation:

-(10r+20)



We get rid of parentheses

12r-10r-20+15=0

We add all the numbers together, and all the variables

2r-5=0

We move all terms containing r to the left, all other terms to the right

2r=5

r=5/2

r=2+1/2

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