3(4r-5)=71/2+3r

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Solution for 3(4r-5)=71/2+3r equation: 



3(4r-5)=71/2+3r

We move all terms to the left:

3(4r-5)-(71/2+3r)=0



Domain of the equation: 2+3r)!=0

We move all terms containing r to the left, all other terms to the right

3r)!=-2

r!=-2/1

r!=-2

r∈R



We add all the numbers together, and all the variables

3(4r-5)-(+3r+71/2)=0

We multiply parentheses

12r-(+3r+71/2)-15=0

We get rid of parentheses

12r-3r-15-71/2=0

We multiply all the terms by the denominator


12r*2-3r*2-71-15*2=0

We add all the numbers together, and all the variables

12r*2-3r*2-101=0

Wy multiply elements

24r-6r-101=0

We add all the numbers together, and all the variables

18r-101=0

We move all terms containing r to the left, all other terms to the right

18r=101

r=101/18

r=5+11/18

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