3(4r-7)-6=2(r+2)-1

Solution for 3(4r-7)-6=2(r+2)-1 equation:

3(4r-7)-6=2(r+2)-1

We move all terms to the left:

3(4r-7)-6-(2(r+2)-1)=0

We multiply parentheses

12r-(2(r+2)-1)-21-6=0


We calculate terms in parentheses: -(2(r+2)-1), so:

2(r+2)-1

We multiply parentheses

2r+4-1

We add all the numbers together, and all the variables

2r+3

Back to the equation:

-(2r+3)


We add all the numbers together, and all the variables

12r-(2r+3)-27=0

We get rid of parentheses

12r-2r-3-27=0

We add all the numbers together, and all the variables

10r-30=0

We move all terms containing r to the left, all other terms to the right

10r=30

r=30/10

r=3