3(4r-7)=33-6r

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Solution for 3(4r-7)=33-6r equation: 



3(4r-7)=33-6r

We move all terms to the left:

3(4r-7)-(33-6r)=0

We add all the numbers together, and all the variables

3(4r-7)-(-6r+33)=0

We multiply parentheses

12r-(-6r+33)-21=0

We get rid of parentheses

12r+6r-33-21=0

We add all the numbers together, and all the variables

18r-54=0

We move all terms containing r to the left, all other terms to the right

18r=54

r=54/18

r=3

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