3(4r-8)=12(8r+12)

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Solution for 3(4r-8)=12(8r+12) equation: 



3(4r-8)=12(8r+12)

We move all terms to the left:

3(4r-8)-(12(8r+12))=0

We multiply parentheses

12r-(12(8r+12))-24=0



We calculate terms in parentheses: -(12(8r+12)), so:

12(8r+12)

We multiply parentheses

96r+144

Back to the equation:

-(96r+144)



We get rid of parentheses

12r-96r-144-24=0

We add all the numbers together, and all the variables

-84r-168=0

We move all terms containing r to the left, all other terms to the right

-84r=168

r=168/-84

r=-2

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