3(4s+1)-9s=6(2-s)

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Solution for 3(4s+1)-9s=6(2-s) equation: 



3(4s+1)-9s=6(2-s)

We move all terms to the left:

3(4s+1)-9s-(6(2-s))=0

We add all the numbers together, and all the variables

3(4s+1)-9s-(6(-1s+2))=0

We add all the numbers together, and all the variables

-9s+3(4s+1)-(6(-1s+2))=0

We multiply parentheses

-9s+12s-(6(-1s+2))+3=0



We calculate terms in parentheses: -(6(-1s+2)), so:

6(-1s+2)

We multiply parentheses

-6s+12

Back to the equation:

-(-6s+12)



We add all the numbers together, and all the variables

3s-(-6s+12)+3=0

We get rid of parentheses

3s+6s-12+3=0

We add all the numbers together, and all the variables

9s-9=0

We move all terms containing s to the left, all other terms to the right

9s=9

s=9/9

s=1

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