3(4s+5)=27

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Solution for 3(4s+5)=27 equation: 



3(4s+5)=27

We move all terms to the left:

3(4s+5)-(27)=0

We multiply parentheses

12s+15-27=0

We add all the numbers together, and all the variables

12s-12=0

We move all terms containing s to the left, all other terms to the right

12s=12

s=12/12

s=1

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