3(4t+1)-12=t-(t+8)

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Solution for 3(4t+1)-12=t-(t+8) equation: 



3(4t+1)-12=t-(t+8)

We move all terms to the left:

3(4t+1)-12-(t-(t+8))=0

We multiply parentheses

12t-(t-(t+8))+3-12=0



We calculate terms in parentheses: -(t-(t+8)), so:

t-(t+8)

We get rid of parentheses

t-t-8

We add all the numbers together, and all the variables

-8

Back to the equation:

-(-8)



We add all the numbers together, and all the variables

12t-1=0

We move all terms containing t to the left, all other terms to the right

12t=1

t=1/12

t=1/12

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