3(4t+1)-16=t-(t+12)

Solution for 3(4t+1)-16=t-(t+12) equation:

Simplifying
3(4t + 1) + -16 = t + -1(t + 12)

Reorder the terms:
3(1 + 4t) + -16 = t + -1(t + 12)
(1 * 3 + 4t * 3) + -16 = t + -1(t + 12)
(3 + 12t) + -16 = t + -1(t + 12)

Reorder the terms:
3 + -16 + 12t = t + -1(t + 12)

Combine like terms: 3 + -16 = -13
-13 + 12t = t + -1(t + 12)

Reorder the terms:
-13 + 12t = t + -1(12 + t)
-13 + 12t = t + (12 * -1 + t * -1)
-13 + 12t = t + (-12 + -1t)

Reorder the terms:
-13 + 12t = -12 + t + -1t

Combine like terms: t + -1t = 0
-13 + 12t = -12 + 0
-13 + 12t = -12

Solving
-13 + 12t = -12

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '13' to each side of the equation.
-13 + 13 + 12t = -12 + 13

Combine like terms: -13 + 13 = 0
0 + 12t = -12 + 13
12t = -12 + 13

Combine like terms: -12 + 13 = 1
12t = 1

Divide each side by '12'.
t = 0.08333333333

Simplifying
t = 0.08333333333