3(4t-4)=2(t-1)

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Solution for 3(4t-4)=2(t-1) equation: 



3(4t-4)=2(t-1)

We move all terms to the left:

3(4t-4)-(2(t-1))=0

We multiply parentheses

12t-(2(t-1))-12=0



We calculate terms in parentheses: -(2(t-1)), so:

2(t-1)

We multiply parentheses

2t-2

Back to the equation:

-(2t-2)



We get rid of parentheses

12t-2t+2-12=0

We add all the numbers together, and all the variables

10t-10=0

We move all terms containing t to the left, all other terms to the right

10t=10

t=10/10

t=1

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