3(4t-6)-10(t+1)=6

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Solution for 3(4t-6)-10(t+1)=6 equation:


Simplifying
3(4t + -6) + -10(t + 1) = 6

Reorder the terms:
3(-6 + 4t) + -10(t + 1) = 6
(-6 * 3 + 4t * 3) + -10(t + 1) = 6
(-18 + 12t) + -10(t + 1) = 6

Reorder the terms:
-18 + 12t + -10(1 + t) = 6
-18 + 12t + (1 * -10 + t * -10) = 6
-18 + 12t + (-10 + -10t) = 6

Reorder the terms:
-18 + -10 + 12t + -10t = 6

Combine like terms: -18 + -10 = -28
-28 + 12t + -10t = 6

Combine like terms: 12t + -10t = 2t
-28 + 2t = 6

Solving
-28 + 2t = 6

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '28' to each side of the equation.
-28 + 28 + 2t = 6 + 28

Combine like terms: -28 + 28 = 0
0 + 2t = 6 + 28
2t = 6 + 28

Combine like terms: 6 + 28 = 34
2t = 34

Divide each side by '2'.
t = 17

Simplifying
t = 17

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