3(4v+1)+2(v-4)=-5

Solution for 3(4v+1)+2(v-4)=-5 equation:

Simplifying
3(4v + 1) + 2(v + -4) = -5

Reorder the terms:
3(1 + 4v) + 2(v + -4) = -5
(1 * 3 + 4v * 3) + 2(v + -4) = -5
(3 + 12v) + 2(v + -4) = -5

Reorder the terms:
3 + 12v + 2(-4 + v) = -5
3 + 12v + (-4 * 2 + v * 2) = -5
3 + 12v + (-8 + 2v) = -5

Reorder the terms:
3 + -8 + 12v + 2v = -5

Combine like terms: 3 + -8 = -5
-5 + 12v + 2v = -5

Combine like terms: 12v + 2v = 14v
-5 + 14v = -5

Add '5' to each side of the equation.
-5 + 5 + 14v = -5 + 5

Combine like terms: -5 + 5 = 0
0 + 14v = -5 + 5
14v = -5 + 5

Combine like terms: -5 + 5 = 0
14v = 0

Solving
14v = 0

Solving for variable 'v'.

Move all terms containing v to the left, all other terms to the right.

Divide each side by '14'.
v = 0

Simplifying
v = 0