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3(4v+4)=6+4(3v-1)
We move all terms to the left:
3(4v+4)-(6+4(3v-1))=0
We multiply parentheses
12v-(6+4(3v-1))+12=0
We calculate terms in parentheses: -(6+4(3v-1)), so:We get rid of parentheses
6+4(3v-1)
determiningTheFunctionDomain 4(3v-1)+6
We multiply parentheses
12v-4+6
We add all the numbers together, and all the variables
12v+2
Back to the equation:
-(12v+2)
12v-12v-2+12=0
We add all the numbers together, and all the variables
10!=0
There is no solution for this equation
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