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3(4v-4)=5(2v+6)
We move all terms to the left:
3(4v-4)-(5(2v+6))=0
We multiply parentheses
12v-(5(2v+6))-12=0
We calculate terms in parentheses: -(5(2v+6)), so:We get rid of parentheses
5(2v+6)
We multiply parentheses
10v+30
Back to the equation:
-(10v+30)
12v-10v-30-12=0
We add all the numbers together, and all the variables
2v-42=0
We move all terms containing v to the left, all other terms to the right
2v=42
v=42/2
v=21
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