3(4w+4)+2w=7(w+7)-30

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Solution for 3(4w+4)+2w=7(w+7)-30 equation: 



3(4w+4)+2w=7(w+7)-30

We move all terms to the left:

3(4w+4)+2w-(7(w+7)-30)=0

We add all the numbers together, and all the variables

2w+3(4w+4)-(7(w+7)-30)=0

We multiply parentheses

2w+12w-(7(w+7)-30)+12=0



We calculate terms in parentheses: -(7(w+7)-30), so:

7(w+7)-30

We multiply parentheses

7w+49-30

We add all the numbers together, and all the variables

7w+19

Back to the equation:

-(7w+19)



We add all the numbers together, and all the variables

14w-(7w+19)+12=0

We get rid of parentheses

14w-7w-19+12=0

We add all the numbers together, and all the variables

7w-7=0

We move all terms containing w to the left, all other terms to the right

7w=7

w=7/7

w=1

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