3(4w-5)=2(6+1)=17

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Solution for 3(4w-5)=2(6+1)=17 equation: 



3(4w-5)=2(6+1)=17

We move all terms to the left:

3(4w-5)-(2(6+1))=0

We add all the numbers together, and all the variables

3(4w-5)-(27)=0

We add all the numbers together, and all the variables

3(4w-5)-27=0

We multiply parentheses

12w-15-27=0

We add all the numbers together, and all the variables

12w-42=0

We move all terms containing w to the left, all other terms to the right

12w=42

w=42/12

w=3+1/2

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