3(4w-5)=2(6w+1)-7

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Solution for 3(4w-5)=2(6w+1)-7 equation: 



3(4w-5)=2(6w+1)-7

We move all terms to the left:

3(4w-5)-(2(6w+1)-7)=0

We multiply parentheses

12w-(2(6w+1)-7)-15=0



We calculate terms in parentheses: -(2(6w+1)-7), so:

2(6w+1)-7

We multiply parentheses

12w+2-7

We add all the numbers together, and all the variables

12w-5

Back to the equation:

-(12w-5)



We get rid of parentheses

12w-12w+5-15=0

We add all the numbers together, and all the variables

-10!=0

There is no solution for this equation

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