3(4x+-1)+-5(x+2)=2(x+-3)+1

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Solution for 3(4x+-1)+-5(x+2)=2(x+-3)+1 equation: 



3(4x+-1)+-5(x+2)=2(x+-3)+1

We move all terms to the left:

3(4x+-1)+-5(x+2)-(2(x+-3)+1)=0

We add all the numbers together, and all the variables

3(4x-1)-5(x+2)-(2(x-3)+1)+=0

We add all the numbers together, and all the variables

3(4x-1)-5(x+2)-(2(x-3)+1)=0

We multiply parentheses

12x-5x-(2(x-3)+1)-3-10=0



We calculate terms in parentheses: -(2(x-3)+1), so:

2(x-3)+1

We multiply parentheses

2x-6+1

We add all the numbers together, and all the variables

2x-5

Back to the equation:

-(2x-5)



We add all the numbers together, and all the variables

7x-(2x-5)-13=0

We get rid of parentheses

7x-2x+5-13=0

We add all the numbers together, and all the variables

5x-8=0

We move all terms containing x to the left, all other terms to the right

5x=8

x=8/5

x=1+3/5

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