3(4x+1)+4(x-2)=

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Solution for 3(4x+1)+4(x-2)= equation:


Simplifying
3(4x + 1) + 4(x + -2) = 0

Reorder the terms:
3(1 + 4x) + 4(x + -2) = 0
(1 * 3 + 4x * 3) + 4(x + -2) = 0
(3 + 12x) + 4(x + -2) = 0

Reorder the terms:
3 + 12x + 4(-2 + x) = 0
3 + 12x + (-2 * 4 + x * 4) = 0
3 + 12x + (-8 + 4x) = 0

Reorder the terms:
3 + -8 + 12x + 4x = 0

Combine like terms: 3 + -8 = -5
-5 + 12x + 4x = 0

Combine like terms: 12x + 4x = 16x
-5 + 16x = 0

Solving
-5 + 16x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + 16x = 0 + 5

Combine like terms: -5 + 5 = 0
0 + 16x = 0 + 5
16x = 0 + 5

Combine like terms: 0 + 5 = 5
16x = 5

Divide each side by '16'.
x = 0.3125

Simplifying
x = 0.3125

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