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3(4x+1)=-3(3x-2)+4x
We move all terms to the left:
3(4x+1)-(-3(3x-2)+4x)=0
We multiply parentheses
12x-(-3(3x-2)+4x)+3=0
We calculate terms in parentheses: -(-3(3x-2)+4x), so:We get rid of parentheses
-3(3x-2)+4x
We add all the numbers together, and all the variables
4x-3(3x-2)
We multiply parentheses
4x-9x+6
We add all the numbers together, and all the variables
-5x+6
Back to the equation:
-(-5x+6)
12x+5x-6+3=0
We add all the numbers together, and all the variables
17x-3=0
We move all terms containing x to the left, all other terms to the right
17x=3
x=3/17
x=3/17
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