3(4x+1)=6(2-x)

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Solution for 3(4x+1)=6(2-x) equation:



3(4x+1)=6(2-x)
We move all terms to the left:
3(4x+1)-(6(2-x))=0
We add all the numbers together, and all the variables
3(4x+1)-(6(-1x+2))=0
We multiply parentheses
12x-(6(-1x+2))+3=0
We calculate terms in parentheses: -(6(-1x+2)), so:
6(-1x+2)
We multiply parentheses
-6x+12
Back to the equation:
-(-6x+12)
We get rid of parentheses
12x+6x-12+3=0
We add all the numbers together, and all the variables
18x-9=0
We move all terms containing x to the left, all other terms to the right
18x=9
x=9/18
x=1/2

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