3(4x+1)=8-(2x-5)

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Solution for 3(4x+1)=8-(2x-5) equation: 



3(4x+1)=8-(2x-5)

We move all terms to the left:

3(4x+1)-(8-(2x-5))=0

We multiply parentheses

12x-(8-(2x-5))+3=0



We calculate terms in parentheses: -(8-(2x-5)), so:

8-(2x-5)

determiningTheFunctionDomain
-(2x-5)+8

We get rid of parentheses

-2x+5+8

We add all the numbers together, and all the variables

-2x+13

Back to the equation:

-(-2x+13)



We get rid of parentheses

12x+2x-13+3=0

We add all the numbers together, and all the variables

14x-10=0

We move all terms containing x to the left, all other terms to the right

14x=10

x=10/14

x=5/7

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