3(4x+14)=10x-2x(x-7)

Solution for 3(4x+14)=10x-2x(x-7) equation:

3(4x+14)=10x-2x(x-7)

We move all terms to the left:

3(4x+14)-(10x-2x(x-7))=0

We multiply parentheses

12x-(10x-2x(x-7))+42=0


We calculate terms in parentheses: -(10x-2x(x-7)), so:

10x-2x(x-7)

We multiply parentheses

-2x^2+10x+14x

We add all the numbers together, and all the variables

-2x^2+24x

Back to the equation:

-(-2x^2+24x)


We get rid of parentheses

2x^2-24x+12x+42=0

We add all the numbers together, and all the variables

2x^2-12x+42=0

a = 2; b = -12; c = +42;
Δ = b2-4ac
Δ = -122-4·2·42
Δ = -192
Delta is less than zero, so there is no solution for the equation