3(4x+16x+40)=3x-40+5x

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Solution for 3(4x+16x+40)=3x-40+5x equation: 



3(4x+16x+40)=3x-40+5x

We move all terms to the left:

3(4x+16x+40)-(3x-40+5x)=0

We add all the numbers together, and all the variables

3(20x+40)-(8x-40)=0

We multiply parentheses

60x-(8x-40)+120=0

We get rid of parentheses

60x-8x+40+120=0

We add all the numbers together, and all the variables

52x+160=0

We move all terms containing x to the left, all other terms to the right

52x=-160

x=-160/52

x=-3+1/13

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