3(4x+19)=21

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Solution for 3(4x+19)=21 equation: 



3(4x+19)=21

We move all terms to the left:

3(4x+19)-(21)=0

We multiply parentheses

12x+57-21=0

We add all the numbers together, and all the variables

12x+36=0

We move all terms containing x to the left, all other terms to the right

12x=-36

x=-36/12

x=-3

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