3(4x+2)+35=16x+2-4x+39

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Solution for 3(4x+2)+35=16x+2-4x+39 equation: 


Simplifying
3(4x + 2) + 35 = 16x + 2 + -4x + 39

Reorder the terms:
3(2 + 4x) + 35 = 16x + 2 + -4x + 39
(2 * 3 + 4x * 3) + 35 = 16x + 2 + -4x + 39
(6 + 12x) + 35 = 16x + 2 + -4x + 39

Reorder the terms:
6 + 35 + 12x = 16x + 2 + -4x + 39

Combine like terms: 6 + 35 = 41
41 + 12x = 16x + 2 + -4x + 39

Reorder the terms:
41 + 12x = 2 + 39 + 16x + -4x

Combine like terms: 2 + 39 = 41
41 + 12x = 41 + 16x + -4x

Combine like terms: 16x + -4x = 12x
41 + 12x = 41 + 12x

Add '-41' to each side of the equation.
41 + -41 + 12x = 41 + -41 + 12x

Combine like terms: 41 + -41 = 0
0 + 12x = 41 + -41 + 12x
12x = 41 + -41 + 12x

Combine like terms: 41 + -41 = 0
12x = 0 + 12x
12x = 12x

Add '-12x' to each side of the equation.
12x + -12x = 12x + -12x

Combine like terms: 12x + -12x = 0
0 = 12x + -12x

Combine like terms: 12x + -12x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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