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3(4x+2)+4=6(2x-4)+8
We move all terms to the left:
3(4x+2)+4-(6(2x-4)+8)=0
We multiply parentheses
12x-(6(2x-4)+8)+6+4=0
We calculate terms in parentheses: -(6(2x-4)+8), so:We add all the numbers together, and all the variables
6(2x-4)+8
We multiply parentheses
12x-24+8
We add all the numbers together, and all the variables
12x-16
Back to the equation:
-(12x-16)
12x-(12x-16)+10=0
We get rid of parentheses
12x-12x+16+10=0
We add all the numbers together, and all the variables
26!=0
There is no solution for this equation
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