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3(4x+2)=2+3(x+4)
We move all terms to the left:
3(4x+2)-(2+3(x+4))=0
We multiply parentheses
12x-(2+3(x+4))+6=0
We calculate terms in parentheses: -(2+3(x+4)), so:We get rid of parentheses
2+3(x+4)
determiningTheFunctionDomain 3(x+4)+2
We multiply parentheses
3x+12+2
We add all the numbers together, and all the variables
3x+14
Back to the equation:
-(3x+14)
12x-3x-14+6=0
We add all the numbers together, and all the variables
9x-8=0
We move all terms containing x to the left, all other terms to the right
9x=8
x=8/9
x=8/9
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