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3(4x+2)=20x-9x^2
We move all terms to the left:
3(4x+2)-(20x-9x^2)=0
We multiply parentheses
-(20x-9x^2)+12x+6=0
We get rid of parentheses
9x^2-20x+12x+6=0
We add all the numbers together, and all the variables
9x^2-8x+6=0
a = 9; b = -8; c = +6;
Δ = b2-4ac
Δ = -82-4·9·6
Δ = -152
Delta is less than zero, so there is no solution for the equation
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