3(4x+2)=38-(7-2x)

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Solution for 3(4x+2)=38-(7-2x) equation: 



3(4x+2)=38-(7-2x)

We move all terms to the left:

3(4x+2)-(38-(7-2x))=0

We add all the numbers together, and all the variables

3(4x+2)-(38-(-2x+7))=0

We multiply parentheses

12x-(38-(-2x+7))+6=0



We calculate terms in parentheses: -(38-(-2x+7)), so:

38-(-2x+7)

determiningTheFunctionDomain
-(-2x+7)+38

We get rid of parentheses

2x-7+38

We add all the numbers together, and all the variables

2x+31

Back to the equation:

-(2x+31)



We get rid of parentheses

12x-2x-31+6=0

We add all the numbers together, and all the variables

10x-25=0

We move all terms containing x to the left, all other terms to the right

10x=25

x=25/10

x=2+1/2

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