3(4x+20)=2(x+40)

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Solution for 3(4x+20)=2(x+40) equation: 



3(4x+20)=2(x+40)

We move all terms to the left:

3(4x+20)-(2(x+40))=0

We multiply parentheses

12x-(2(x+40))+60=0



We calculate terms in parentheses: -(2(x+40)), so:

2(x+40)

We multiply parentheses

2x+80

Back to the equation:

-(2x+80)



We get rid of parentheses

12x-2x-80+60=0

We add all the numbers together, and all the variables

10x-20=0

We move all terms containing x to the left, all other terms to the right

10x=20

x=20/10

x=2

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