3(4x+3)+4(6x+1)=45

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Solution for 3(4x+3)+4(6x+1)=45 equation:



3(4x+3)+4(6x+1)=45
We move all terms to the left:
3(4x+3)+4(6x+1)-(45)=0
We multiply parentheses
12x+24x+9+4-45=0
We add all the numbers together, and all the variables
36x-32=0
We move all terms containing x to the left, all other terms to the right
36x=32
x=32/36
x=8/9

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