3(4x+3)+4(6x+1)=45

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Solution for 3(4x+3)+4(6x+1)=45 equation: 



3(4x+3)+4(6x+1)=45

We move all terms to the left:

3(4x+3)+4(6x+1)-(45)=0

We multiply parentheses

12x+24x+9+4-45=0

We add all the numbers together, and all the variables

36x-32=0

We move all terms containing x to the left, all other terms to the right

36x=32

x=32/36

x=8/9

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