3(4x+3)+43=4(6x+1)

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Solution for 3(4x+3)+43=4(6x+1) equation: 



3(4x+3)+43=4(6x+1)

We move all terms to the left:

3(4x+3)+43-(4(6x+1))=0

We multiply parentheses

12x-(4(6x+1))+9+43=0



We calculate terms in parentheses: -(4(6x+1)), so:

4(6x+1)

We multiply parentheses

24x+4

Back to the equation:

-(24x+4)



We add all the numbers together, and all the variables

12x-(24x+4)+52=0

We get rid of parentheses

12x-24x-4+52=0

We add all the numbers together, and all the variables

-12x+48=0

We move all terms containing x to the left, all other terms to the right

-12x=-48

x=-48/-12

x=+4

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