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3(4x+3)-2(x+1)=2(x+3)
We move all terms to the left:
3(4x+3)-2(x+1)-(2(x+3))=0
We multiply parentheses
12x-2x-(2(x+3))+9-2=0
We calculate terms in parentheses: -(2(x+3)), so:We add all the numbers together, and all the variables
2(x+3)
We multiply parentheses
2x+6
Back to the equation:
-(2x+6)
10x-(2x+6)+7=0
We get rid of parentheses
10x-2x-6+7=0
We add all the numbers together, and all the variables
8x+1=0
We move all terms containing x to the left, all other terms to the right
8x=-1
x=-1/8
x=-1/8
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