3(4x+3)=2x-4(3-x)+10

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Solution for 3(4x+3)=2x-4(3-x)+10 equation:



3(4x+3)=2x-4(3-x)+10
We move all terms to the left:
3(4x+3)-(2x-4(3-x)+10)=0
We add all the numbers together, and all the variables
3(4x+3)-(2x-4(-1x+3)+10)=0
We multiply parentheses
12x-(2x-4(-1x+3)+10)+9=0
We calculate terms in parentheses: -(2x-4(-1x+3)+10), so:
2x-4(-1x+3)+10
We multiply parentheses
2x+4x-12+10
We add all the numbers together, and all the variables
6x-2
Back to the equation:
-(6x-2)
We get rid of parentheses
12x-6x+2+9=0
We add all the numbers together, and all the variables
6x+11=0
We move all terms containing x to the left, all other terms to the right
6x=-11
x=-11/6
x=-1+5/6

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