3(4x+4)-20=13x-4

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Solution for 3(4x+4)-20=13x-4 equation: 



3(4x+4)-20=13x-4

We move all terms to the left:

3(4x+4)-20-(13x-4)=0

We multiply parentheses

12x-(13x-4)+12-20=0

We get rid of parentheses

12x-13x+4+12-20=0

We add all the numbers together, and all the variables

-1x-4=0

We move all terms containing x to the left, all other terms to the right

-x=4

x=4/-1

x=-4

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