3(4x+4)=16x+11-4x+1

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Solution for 3(4x+4)=16x+11-4x+1 equation:


Simplifying
3(4x + 4) = 16x + 11 + -4x + 1

Reorder the terms:
3(4 + 4x) = 16x + 11 + -4x + 1
(4 * 3 + 4x * 3) = 16x + 11 + -4x + 1
(12 + 12x) = 16x + 11 + -4x + 1

Reorder the terms:
12 + 12x = 11 + 1 + 16x + -4x

Combine like terms: 11 + 1 = 12
12 + 12x = 12 + 16x + -4x

Combine like terms: 16x + -4x = 12x
12 + 12x = 12 + 12x

Add '-12' to each side of the equation.
12 + -12 + 12x = 12 + -12 + 12x

Combine like terms: 12 + -12 = 0
0 + 12x = 12 + -12 + 12x
12x = 12 + -12 + 12x

Combine like terms: 12 + -12 = 0
12x = 0 + 12x
12x = 12x

Add '-12x' to each side of the equation.
12x + -12x = 12x + -12x

Combine like terms: 12x + -12x = 0
0 = 12x + -12x

Combine like terms: 12x + -12x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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