3(4x+5)-20=10x+15

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Solution for 3(4x+5)-20=10x+15 equation: 



3(4x+5)-20=10x+15

We move all terms to the left:

3(4x+5)-20-(10x+15)=0

We multiply parentheses

12x-(10x+15)+15-20=0

We get rid of parentheses

12x-10x-15+15-20=0

We add all the numbers together, and all the variables

2x-20=0

We move all terms containing x to the left, all other terms to the right

2x=20

x=20/2

x=10

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