3(4x+5)=-40+43

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Solution for 3(4x+5)=-40+43 equation: 



3(4x+5)=-40+43

We move all terms to the left:

3(4x+5)-(-40+43)=0

We add all the numbers together, and all the variables

3(4x+5)-3=0

We multiply parentheses

12x+15-3=0

We add all the numbers together, and all the variables

12x+12=0

We move all terms containing x to the left, all other terms to the right

12x=-12

x=-12/12

x=-1

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