3(4x+5)=2(6x-3)+21

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Solution for 3(4x+5)=2(6x-3)+21 equation: 



3(4x+5)=2(6x-3)+21

We move all terms to the left:

3(4x+5)-(2(6x-3)+21)=0

We multiply parentheses

12x-(2(6x-3)+21)+15=0



We calculate terms in parentheses: -(2(6x-3)+21), so:

2(6x-3)+21

We multiply parentheses

12x-6+21

We add all the numbers together, and all the variables

12x+15

Back to the equation:

-(12x+15)



We get rid of parentheses

12x-12x-15+15=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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