3(4x+5)=x-40

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Solution for 3(4x+5)=x-40 equation: 



3(4x+5)=x-40

We move all terms to the left:

3(4x+5)-(x-40)=0

We multiply parentheses

12x-(x-40)+15=0

We get rid of parentheses

12x-x+40+15=0

We add all the numbers together, and all the variables

11x+55=0

We move all terms containing x to the left, all other terms to the right

11x=-55

x=-55/11

x=-5

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