3(4x+6)=19x+1-7x+17

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Solution for 3(4x+6)=19x+1-7x+17 equation: 



3(4x+6)=19x+1-7x+17

We move all terms to the left:

3(4x+6)-(19x+1-7x+17)=0

We add all the numbers together, and all the variables

3(4x+6)-(12x+18)=0

We multiply parentheses

12x-(12x+18)+18=0

We get rid of parentheses

12x-12x-18+18=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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