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3(4x+6)=6(2x+1)+12
We move all terms to the left:
3(4x+6)-(6(2x+1)+12)=0
We multiply parentheses
12x-(6(2x+1)+12)+18=0
We calculate terms in parentheses: -(6(2x+1)+12), so:We get rid of parentheses
6(2x+1)+12
We multiply parentheses
12x+6+12
We add all the numbers together, and all the variables
12x+18
Back to the equation:
-(12x+18)
12x-12x-18+18=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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