3(4x-1)-(7-4x)=40

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Solution for 3(4x-1)-(7-4x)=40 equation:


Simplifying
3(4x + -1) + -1(7 + -4x) = 40

Reorder the terms:
3(-1 + 4x) + -1(7 + -4x) = 40
(-1 * 3 + 4x * 3) + -1(7 + -4x) = 40
(-3 + 12x) + -1(7 + -4x) = 40
-3 + 12x + (7 * -1 + -4x * -1) = 40
-3 + 12x + (-7 + 4x) = 40

Reorder the terms:
-3 + -7 + 12x + 4x = 40

Combine like terms: -3 + -7 = -10
-10 + 12x + 4x = 40

Combine like terms: 12x + 4x = 16x
-10 + 16x = 40

Solving
-10 + 16x = 40

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '10' to each side of the equation.
-10 + 10 + 16x = 40 + 10

Combine like terms: -10 + 10 = 0
0 + 16x = 40 + 10
16x = 40 + 10

Combine like terms: 40 + 10 = 50
16x = 50

Divide each side by '16'.
x = 3.125

Simplifying
x = 3.125

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