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3(4x-1)8x=17
We move all terms to the left:
3(4x-1)8x-(17)=0
We multiply parentheses
96x^2-24x-17=0
a = 96; b = -24; c = -17;
Δ = b2-4ac
Δ = -242-4·96·(-17)
Δ = 7104
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7104}=\sqrt{64*111}=\sqrt{64}*\sqrt{111}=8\sqrt{111}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-8\sqrt{111}}{2*96}=\frac{24-8\sqrt{111}}{192} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+8\sqrt{111}}{2*96}=\frac{24+8\sqrt{111}}{192} $
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