3(4x-1)=-2x+19+8x-4

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Solution for 3(4x-1)=-2x+19+8x-4 equation: 



3(4x-1)=-2x+19+8x-4

We move all terms to the left:

3(4x-1)-(-2x+19+8x-4)=0

We add all the numbers together, and all the variables

3(4x-1)-(6x+15)=0

We multiply parentheses

12x-(6x+15)-3=0

We get rid of parentheses

12x-6x-15-3=0

We add all the numbers together, and all the variables

6x-18=0

We move all terms containing x to the left, all other terms to the right

6x=18

x=18/6

x=3

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