3(4x-1)=-8(x-4)+5

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Solution for 3(4x-1)=-8(x-4)+5 equation: 



3(4x-1)=-8(x-4)+5

We move all terms to the left:

3(4x-1)-(-8(x-4)+5)=0

We multiply parentheses

12x-(-8(x-4)+5)-3=0



We calculate terms in parentheses: -(-8(x-4)+5), so:

-8(x-4)+5

We multiply parentheses

-8x+32+5

We add all the numbers together, and all the variables

-8x+37

Back to the equation:

-(-8x+37)



We get rid of parentheses

12x+8x-37-3=0

We add all the numbers together, and all the variables

20x-40=0

We move all terms containing x to the left, all other terms to the right

20x=40

x=40/20

x=2

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